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From "Winnebeck, Jason" <>
Subject RE: Groovy Hash Calculations
Date Fri, 04 Mar 2016 14:40:11 GMT
Here is how I would do it. I provide both a “short” solution and a “long” one. I would
use the “short” solution if I was making for example a developer only tool and I knew
I was only hashing small things for example a configuration file in a build script and want
a one-liner. Otherwise I’d use the “long” version.

//If the content is guaranteed to be short:
def content = new ByteArrayInputStream("Here be dragons".bytes)
println MessageDigest.getInstance("SHA1").digest(content.bytes).encodeHex()

//If the content might be arbitrarily long:
content = new ByteArrayInputStream("Here be dragons".bytes)
def digest = MessageDigest.getInstance("SHA1")
content.eachByte(4096) { bytes, len ->
  digest.update(bytes, 0, len)
println digest.digest().encodeHex()


From: Gerald Wiltse []
Sent: Friday, March 04, 2016 9:18 AM
Subject: Groovy Hash Calculations

Hello All,

I have this block, it's pretty compressed, just wondering if there is a more groovy way to
handle reading the buffer and computing the hash.

        def messageDigest = MessageDigest.getInstance("SHA1")
        def dis = new DigestInputStream(content, messageDigest)
        byte[] buffer = new byte[1024];
        while ( != -1) {}
        def sha1Hex = new BigInteger(1, messageDigest.digest()).toString(16).padLeft(40, '0')

Gerald R. Wiltse<>

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