Are you doing more than just removing nodes?  The following seems to retain the namespace prefixes when serializing back out after removing a node.

import groovy.xml.*

String xml = '''
<a:root xmlns:a="urn:a" xmlns:b="urn:b" xmlns:c="urn:c">

def root = new XmlSlurper().parseText(xml)
root.child2.replaceNode {}

String newXml = XmlUtil.serialize(root)
def newRoot = new XmlSlurper().parseText(newXml)

println XmlUtil.serialize(newRoot)
assert newRoot.lookupNamespace('a') == 'urn:a'
assert newRoot.child3.lookupNamespace('c') == 'urn:c'

Don't believe there's a defined way to get all the namespaces from the original files, other than possibly picking at the non-public namespaceTagHints field or by visiting each node and using #namespaceURI() to get it's namespace.

On Mon, Apr 11, 2016 at 9:40 AM, garneke <> wrote:
I have a requirement in my application to receive xml files from a user and
filter out specific nodes based on a configuration option ( accepts GPath
String ).

This is fine.
I can use XmlSlurper to parse the file and with the defined GPath I can find
and remove the node and rewrite the file.

My application is generic and can accept any XML.
My user base is not terribly savvy so I need to be able to have the GPath
specified without the namespace prefixes.   This is also fine if the
XmlSlurper is created to be namespace aware.

*The problem is...*
If my XmlSlurper is namespace aware and I remove a node, when I re-write the
XML file all of the namespace prefixes get altered to "tag0:", "tag1:",
"tag2:" etc.

Is there a way to produce the XML with its original namespace prefixes?
Is there someway I can query the original file for its namespaces and use
that declare the namespaces for the slurper?

Thanks in advance for your help.

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